字典推导式
mcase = {'a': 10, 'b': 34, 'A': 7, 'Z': 3}
mcase_frequency = {
k.lower(): mcase.get(k.lower(), 0) + mcase.get(k.upper(), 0)
for k in mcase.keys()
}
# mcase_frequency == {'a': 17, 'z': 3, 'b': 34}{v: k for k, v in some_dict.items()}最后更新于
这有帮助吗?